The intercepts made by a line on the axes are equal in magnitude, but
opposite in signs. If the line passes through the point (5, 7) then find the
equation of the line. Express the equation of the line (i) in gradient from
(ii) in normal form.
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here is your solution .......
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Step-by-step explanation:
Passing through (5,7)
let us take intercept form let k be the intercept of x axis , so intercept of Y axis be -k
so equation of line will be
x/k + y / -k = 1
Put (5,7 )
in the equation
5/k - 7 /k = 1
⇒ k = -2
so equation of the of line is x -y =-2
⇒y-x= 2
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