Question

The interest on ₹515 is ₹55 in a certain time period. Find the interest on ₹927 in the same time period.
please answer me fast..​

Answer 1

Step-by-step explanation:

Given :-

The interest on ₹515 is ₹55 in a certain time period.

To find :-

The interest on ₹927 in the same time period.

Solution :-

Given that

The principal (P) = ₹515

Simple Interest (S.I) = ₹55

Let the time be T years

Let the Rate of Interest be R %

We know that

Simple Interest = PTR/100

=> 55 = (515×T×R)/100

=> 55 = 515TR/100

=> 55 = 103TR/20

=> 55×20 = 103TR

=> 1100 = 103TR

=> 103TR = 1100

=> TR = 1100/103

=> T = 1100/(103R) Years

Therefore, Time = 1100/(103R) Years

Since , Time periods are same.

Rate of interest = R%

Since, Rate of Interests are same

Given that

Principal (P) = ₹927

Time (T) = 1100/(103R) Years

We know that

Simple Interest = PTR/100

=> SI = (927×1100×R)/(103R×100)

=> SI = 927×11/103

=> SI = 9×11

=> SI = 99

Therefore, Simple Interest = ₹99

Answer :-

The required Simple Interest is ₹99

Used formulae:-

→ Simple Interest = PTR/100

• P = Principal
• T = Time
• R = Rate of Interest

Answer 2

Information mentioned in above question :

• The interest on ₹515 is ₹55 in a certain time period.

What we have to find out :

• The required interest on ₹927 in the same time period

Assumption :

Consider the the time be t years and rate be r %

Formula used :

$\rm \implies \: S. I = \dfrac{P \times R \times T}{100}$

where ,

• P = Principal,

• R = Rate of Interest in % per annum

• T = Time to calculated the number of years.

• The rate of interest is in percentage r% and is to be written as r/100.

We have :

➡ Principal (P ) = ₹515

➡Rate (R) = r

➡ Time (T) = t

➡ Simple Interest (S.I ) = ₹55

Calculation :

• Put the given values in above formula and solve

$\rm \longrightarrow \: 55= \dfrac{515\times \: r \times t}{100}$

$\rm \implies \:r = \dfrac{55}{5.15 \: t}$

Now :

• For ₹927 by using the same formula and by putting the above values we get :

➡ Principal (P ) = ₹ 927

➡Rate (R) = 55 / 5.15 t

➡ Time (T) = t

$\rm \longrightarrow \: S.I = \dfrac{927\times \: r \times t}{100}$

$\rm \longrightarrow \: S.I = \dfrac{927\times \: \dfrac{55}{5.15 \: \cancel{t}} \times \cancel{t}}{100}$

$\rm \longrightarrow \: S.I = \dfrac{927\times \: 55}{100 \times 5.15}$

$\rm \longrightarrow \: S.I = \dfrac{50985}{515}$

$\rm \implies \: S.I =99$

Therefore :

• The required interest on ₹927 in the same time period is ₹ 99

Verification :

$\sf \mapsto \: S.I = \dfrac{927 \times 55}{515}$

$\sf \mapsto \: S.I = \dfrac{50,985}{515}$

$\bf \mapsto \: S.I = 99$

Hence Proved ❤️