Question

The interference pattern is obtained with two
coherent light sources of intensity ratio n. In the
interference pattern, the ratio
Imax -- /min
will be

Answer 1

Answer:

Ratio of maximum and minimum intensity is given as

$\frac{I_{max}}{I_{min}} = \frac{(\sqrt{n} + 1)^2}{(\sqrt{n} - 1)^2}$

Explanation:

As we know that the ratio of two intensity of the given waves is

$n = \frac{I_1}{I_2}$

now we know that maximum intensity due to superposition of coherent waves is given by

$I_{max} = (\sqrt{I_1} + \sqrt{I_2})^2$

similarly minimum frequency due to superposition of two coherent waves is given as

$I_{min} = (\sqrt{I_1} - \sqrt{I_2})^2$

now we have to find the ratio of maximum and minimum intensity

so we have

$\frac{I_{max}}{I_{min}} = \frac{(\sqrt{I_1} + \sqrt{I_2})^2}{(\sqrt{I_1} - \sqrt{I_2})^2}$

$\frac{I_{max}}{I_{min}} = \frac{(\sqrt{I_1/I_2} + 1)^2}{(\sqrt{I_1/I_2} - 1)^2}$

now we have

$\frac{I_{max}}{I_{min}} = \frac{(\sqrt{n} + 1)^2}{(\sqrt{n} - 1)^2}$

#Learn

Topic : Interference of coherent waves

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