the interior angle of a hexagon are x°,(2x+25°),(4x+10°),(3x-20°),(x+45°),and(5x+20°) find angle of each angle
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Step-by-step explanation:
let hexagon is ABCDEF.
A = x°. eq (1)
B =3x°+25°. eq (2)
C=4x°+10°. eq (3)
D=3x°+20°. eq (4)
E=x°+45°. eq (5)
F=5x°+20°. eq ( 6)
A+B+C+D+E+F=360°
x°+3x°+25°+4x°+10°+3x°+20°+x°+45°+5x°+20°=360°
14x°+120°=360°
14x°=360°-120°
14x°=240°
x=240°/14°
x=17.14°
the put value of x in eq 1, 2 ,3,4,5,6
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