the interior angle of a pentagon are in the ratio 4: 5 :6:7 :5 .find each angle of the Pentagon
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Answered by
3
let it be x
so it become
4x+5x+6x+7x+5x=
so it become
4x+5x+6x+7x+5x=
Glennjohnsijo:
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Answered by
17
Step-by-step explanation:
sum of interior angles of pentagon= 540
let the interior angles of the given pentagon be= 4x, 5x, 6x, 7x, 5x.
hence, 4x+5x+6x+7x+5x=540
27x=540
x=20.
now substituting value of x in the angles=
4x= 4*20= 80 degree
5x= 5*20= 100 degree
6x= 6*20= 120 degree
7x= 7*20= 140 degree
5x= 5*20= 100 degree
therefore, angles of the pentagon are 80, 100, 120, 140, 100.
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