Math, asked by kavithakasala, 11 hours ago

the interior angle of a regular polygon exceeds its exterior angle by 90 degree the sides of the given polygon will be

Answers

Answered by Rekhasundhar
0

Answer:

10

Step-by-step explanation:

Let the exterior angle be x

we are given that the interior angle of a regular polygon exceeds its exterior angle by 108

So, interior angle = x+108

Since we know that the sum of interior angle and exterior angle is 180°

So, x+x+108=180x+x+108=180

2x+108=1802x+108=180

2x=722x=72

x=36x=36

Formula : 180 \times \frac{n-2}{n}=\text{interior angle}180×nn−2=interior angle

180 \times \frac{n-2}{n}=36+108180×nn−2=36+108

n=10n=10

Hence a polygon has 10 sides

Step-by-step explanation:

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