the interior angle of a regular polygon exceeds its exterior angle by 90 degree the sides of the given polygon will be
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Answer:
10
Step-by-step explanation:
Let the exterior angle be x
we are given that the interior angle of a regular polygon exceeds its exterior angle by 108
So, interior angle = x+108
Since we know that the sum of interior angle and exterior angle is 180°
So, x+x+108=180x+x+108=180
2x+108=1802x+108=180
2x=722x=72
x=36x=36
Formula : 180 \times \frac{n-2}{n}=\text{interior angle}180×nn−2=interior angle
180 \times \frac{n-2}{n}=36+108180×nn−2=36+108
n=10n=10
Hence a polygon has 10 sides
Step-by-step explanation:
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