The interior angle of a regular polygon is 1350. Find the number of side of the regular polygon.
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Answer:
question is wrong as u r getting since in decimal which is not possible
Step-by-step explanation:
answer is coming9.5
pls mark me brainliest
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Answer:
8.
Step-by-step explanation:
The sum of the interior angles of a p-sided polygon is (p-2)×180°.
So each angle of a regular p-sided polygon is (p-2)/p×180°.
Let n be the number of sides of a regular polygon whose interior angles are each 135°.
Then (n-2))n×180° = 135°.
So (n-2)/n×180°/180° = 135°/180°.
So (n-2)/n = 135/180.
So (n-2)/n = ¾.
So (n-2)/n×n = ¾n.
So n-2 = ¾n.
So n-2-¾n+2 = ¾n-¾n+2.
So (1-¾)n = 2.
So (4/4-¾)n = 2.
So (4-3)/4×n = 2.
So ¼n = 2.
So ¼n×4 = 2×4.
So n = 8.
CHECK:
If p = 8, then the magnitude of each side is:
(p-2)/p×180°
= (8-2)/8×180°
= 6/8×180°
= ¾×180°
= 135°. ✓
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