Math, asked by srsanjana9027, 1 year ago

The interior angle of an quadrilateral are in ap whose common difference is 15 find the largest angles

Answers

Answered by navjotsingh10
4
let the first angle be =x
let the second angle be=x+15
third angle=x+15+15
=x+30
fourth angle=x+45

x+x+15+x+30+x+45=360°
4x+90=360°
4x=360-90
4x=270
x=270/4
x=67.5

first angle = 67.5°
second angle= 67.5+15
=82.5°
third angle=67.5+30
=97.5°
fourth angle=67.5+45
=112.5°



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Answered by maria920k
1

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