The interior angle of an quadrilateral are in ap whose common difference is 15 find the largest angles
Answers
Answered by
4
let the first angle be =x
let the second angle be=x+15
third angle=x+15+15
=x+30
fourth angle=x+45
x+x+15+x+30+x+45=360°
4x+90=360°
4x=360-90
4x=270
x=270/4
x=67.5
first angle = 67.5°
second angle= 67.5+15
=82.5°
third angle=67.5+30
=97.5°
fourth angle=67.5+45
=112.5°
i hope this helps you. plz mark it brainleist
let the second angle be=x+15
third angle=x+15+15
=x+30
fourth angle=x+45
x+x+15+x+30+x+45=360°
4x+90=360°
4x=360-90
4x=270
x=270/4
x=67.5
first angle = 67.5°
second angle= 67.5+15
=82.5°
third angle=67.5+30
=97.5°
fourth angle=67.5+45
=112.5°
i hope this helps you. plz mark it brainleist
Answered by
1
Answer:
Hope this helps!!
Step-by-step explanation:
Pls mark as brainliest!!
Attachments:
Similar questions