the interior angles of a decagon which are given as (3x+10)°.(2x + 7)º. (4x - 3)º(5x-2)°(2x+15) (3x + 2), (x+3)(2x+5), (3x - 1)º and (3x + 4)º.
Answers
Answered by
24
Answer:
Total of interior angles = ( 2n-4) Rt L
n = 10, Total = 1440°
Total of the intr. angles given =
28X +40
28x+40=1440
28x=14oo
x=50
The angles are, 160,107, 197,248,115,152,53,105,149, I54
Step-by-step explanation:
.
Answered by
11
hopes that this is helpful to you
Attachments:
Similar questions