The interior angles of a pentagon are 100degrees,x,(3x+30),(2x-10) 80 degree find x
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0
Answer:
Correct option is
B
68
o
Given angle of pentagon are x,x+20,x+40,x+60 and x+80
We know that sum of angle of pentagon =540
0
Then x+x+20+x+40+x+60+x+80=540
⇒5x+200=540
⇒5x=540−200
⇒x=
5
340
=68
o
Then smallest angle of pentagon is 68
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