Question

the interior angles of a pentagon are a degree a + 20 degrees a+ 40 Degrees A + 60 degrees and a + 80 degrees find the smallest angle of the Pentagon ​

Answer 1

Answer:

The sum of all interior angles of a pentagon is 540°

So,

a°+(a°+20°)+(a°+40°) +(a°+60°) +(a°+80°)

=540°

5a° + 200° = 540°

5a° = 540°- 200°

5a° = 340°

a° = 68°

Smallest angle of pentagon is a°

So smallest angle of the pentagon will be 68°.

Answer 2

Answer:

sum of interior angles=(n-2)*180.

so,

(n-2)*180=1800

(n-2)=10. (note this step)

n=12

so,

the number of sides of the polygon is 12.

Step-by-step explanation:

plzzzzzzzzzzzzzz make me as a Braniliest