Question

The interior angles of a pentagon are in the ratio 4:5:6:7:5.Find each angle of the pentagon

Answer 1

let the ratios be 4x:5x:6x:7x:5x

then 4x + 5x + 6x + 7x + 5x = 540 [ sum of angles of pentagon ]

=> 27x = 540

=> x = 540/27

=> x = 20

therefore angles of pentagon are 80 , 100 , 120 , 140 , 100

Answer 2

4x+5x+6x+7x+5x=(5-2)*180
27x=540
x=20
so angles are
4*20=80
5*20=100
6*20=120
7*20=140
5*20=100