The interior angles of a polygon are in A.P. If the smallest angle is 100° and the common difference
is 4°, then the number of sides is
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Answer:
sumofinterioranglesofannsidedpolygon=180(n−2)
Angles are in AP
Smallest angle =a=100
0
Common difference =d=4
0
Sum of n terms
2
n
[2a+(n−1)d]
Sum of n terms
2
n
[200+(n−1)4]
sumofterms⇒n[100+2(n−1)]
......(2)
(1)=(2)
⇒n[100+2(n−1)]=180(n−2)
⇒100n+2n
2
−2n=180n−360
⇒2n
2
=82n−360
⇒n
2
−41n+180=0
⇒n
2
−36n−5n+180=0
⇒n(n−36)−6(n−36)=0
⇒(n−5)(n−36)=0
⇒n=5 or 36
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