The interior angles of a polygon are in Ap. The smallest angle is 52°and the common difference is 8°. Find the no. of sides of polygon.
Answers
Answer:the first angle given is 52
Other three will be in sum of 180-52
=128
So by creating AP
We could find this
a=52 d=8
Step-by-step explanation:
Answer:
Step-by-step explanation:
a=52,d=8
Sn=n/2(2(52)+(n-1)8)
n/2(104+8n-8)
n/2(96+8n)---/(1)
And wkt,
(n-2)180-----(2). (to findinterior
sides a Of
polygon)
Now equate (1) and (2)
n/2(96+8n)=(n-2)180
8n*2+96n=360n-720
8n*2+96n-360n+720=0
8n*2-264n+720=0(divide by 8)
n*2-33n+90=0
n*2-30n-3n+90=0
n(n-30)-3(n-30)=0
(n-3)(n-30)=0
n-3=0
n=3
And
n-30=0
n=30
As 'N's can't be more then 9,So
n=3
Therefore ,number of sides in polygon is 3
I hope this answer may help you all