The interior angles of a quadilateral are (2x+15),(2x-5),(3x+75)and (3x-25).find the value of x.smallest interior angle of a quadilateral , the largest interior angle of a quadilateral and the largest exterior angle
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(2x+15)+(2x-5)+(3x+75)+(3x-25) = 360
(since sum of all interior angle of a quadrilateral= 360)
10x+60 = 360
10x =360 - 60
10x = 300
X=300/10
X=30
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