Question

The internal and external diameter of steel pipe of length 140cm are 8cm and 10cm respectively find the volume of steel and thickness of metal

Answer 1

Given


Length of pipe = 140cm

External diameter =10cm

External Radius (r1) =5cm

Internal diameter =8cm

Internal Radius (r2) =4cm

So volume of steel = volume of pipe with external diameter - volume of pipe with internal diameter

(volume of pipe = pi r² h)


$volume \: of \: steel = \pi {r1}^{2} h - \pi {r2}^{2} hr$
$= \pi \: h( {r1}^{2} - {r2}^{2} )$
$= \pi \times 140 \times ( {5}^{2} - {4}^{2} )$
=
$\pi \times 140 \times (25 - 16)$

$= \frac{22}{7} \times 140 \times 9$
$= 22 \times 20 \times 9$
=3960cm³

Thickness of the metal = (external Radius - internal Radius)

=5-4

=1cm

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Answer 2

Step-by-step explanation:

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