The internal and external diameter of the hollow hemispherical vessel are 16 cm and 12cm respectively. If the cost of painting 1cm2 of the surface area is rs 5.50. Find the total cost of painting the vessel.
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hi frnd
given,
internal diameter=12 cm
external diameter =16cm
radius of internal =12/2=6cm
radius of external=16/2=8cm
surface area(internal)=2πr²=2×22/7 ×6×6=2×22×6×6/7=227cm²
surface area (external)=2πR²=2×22/7 ×8×8
=2×22×8×8/7=403cm²
cost of painting = cost of internal+ cost of external+cost of the ring= 2(227)+2(403)+2(π(R²-r²)
=454+806+2(22/7(8²-6²)
=1260+44/7(64-36)
=1260+44/7(28)
=1260+44×4
=1260+176=1436 approx
because the answer come 1436 I take the next number. so it came. if u can use this process. if u want the exact value.
hope this helps you
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Step-by-step explanation:plz ignore that 18 table
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