the internal and external radii of a hollow cylinder are 12cm and 18cm respectively.if its height is 14cm then find its curved surface area and total surface area
Answers
Answered by
7
Solution :
Given R1= 12 , R2= 18 and h = 14
1) Curved Surface area of the cylinder = 2 π r h
Of R1 =2π12*14
=1055.57sq.cm
of R2=2π18*14
= 1583.36sq cm
2) Total surface Area
=curved surface areas of R1+curved surface area of R2
+2π(R2²-R1²).
=1055.57+1583.36+(2π(324-44))
= 2638.93+2( 565.48)
= 3769.89 sq.cm
Given R1= 12 , R2= 18 and h = 14
1) Curved Surface area of the cylinder = 2 π r h
Of R1 =2π12*14
=1055.57sq.cm
of R2=2π18*14
= 1583.36sq cm
2) Total surface Area
=curved surface areas of R1+curved surface area of R2
+2π(R2²-R1²).
=1055.57+1583.36+(2π(324-44))
= 2638.93+2( 565.48)
= 3769.89 sq.cm
Basilisk:
i have trobule with the editing stuff
Solution :
Given R1= 12 , R2= 18 and h = 14
1) Curved Surface area of the cylinder = 2 π r h
Of R1 =2π12*14
=1055.57sq.cm
of R2=2π18*14
= 1583.36sq cm
2) Total surface Area
=curved surface areas of R1+curved surface area of R2+2π(R2²-R1²).
=1055.57+1583.36+(2π(324-44))
= 2638.93+2( 565.48)
= 3769.89 sq.cm
Given R1= 12 , R2= 18 and h = 14
1) Curved Surface area of the cylinder = 2 π r h
Of R1 =2π12*14
=1055.57sq.cm
of R2=2π18*14
= 1583.36sq cm
2) Total surface Area
=curved surface areas of R1+curved surface area of R2+2π(R2²-R1²).
=1055.57+1583.36+(2π(324-44))
= 2638.93+2( 565.48)
= 3769.89 sq.cm
Answered by
5
lts curved surface area=1584and total surface area=3769
Similar questions