the internal and external radii of a hollow hemispherical shell are 3cm and 5cm respectievely .find the TSA and CSA of the shell
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CSA internal=pi r =22/7*3 =66/7 sq cm
External = pi*R = 22/7*5 =110/7 sq cm
TSA = cSA internally + CSA ex+ are on top = 66/7+ 110/7 + pi(25-9)
= (66+110+16*22)/7
=528/7 = 75.42sqcm
External = pi*R = 22/7*5 =110/7 sq cm
TSA = cSA internally + CSA ex+ are on top = 66/7+ 110/7 + pi(25-9)
= (66+110+16*22)/7
=528/7 = 75.42sqcm
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