Question

The internal circumference of a circular road is 440 m. It is 10 m wide every where.
Find the cost of levelling the road at the rate of * 70 per square metre. (it = 22/7)​

Answer 1

Answer:

Answer

3.3/5

27

gayathrikn42com

let the smaller radius be r and bigger radius = R

inner circumference= 440m

2*22/7*r= 440m

r=70m

R= 70+14= 84m

area of track= area of bigger circle - area of smaller circle

= pie R^2 -pie r^2

= 2146m

cost of levelling = 25 paise/m

cost = 13412.5 rupees

circumference of bigger circle = pie R^2

= 22176m

cost = 5*22176

= 110880 rs

I HOPE IT IS CORRECT AND HELPFUL