the internal dimensions of a rectangular box are 12 cm *x cm* 9 cmif the length of the longest rod that can be placed in this box is 17 cm find x
Answers
Answered by
34
simce diagonal=root under (L^2+B^2+h^2)
also,diagonal=17
root under(12^2+x^2+9^2)=17
squaring both sides:
144+x^2+81=289
225+x^2=289
x^2=289-225=64
x=root under 64=8cm
also,diagonal=17
root under(12^2+x^2+9^2)=17
squaring both sides:
144+x^2+81=289
225+x^2=289
x^2=289-225=64
x=root under 64=8cm
Answered by
21
Dear Student,
● Answer -
x = 8 cm
◆ Explanation -
Given that internal dimensions of a rectangular box are 12 cm × x cm × 9 cm.
l = 12 cm
b = x cm
h = 9 cm
Length of the longest rod that can be placed in this box is equal to its diagonal.
Diagonal of rectangular box is given as -
d^2 = l^2 + b^2 + h^2
17^2 = 12^2 + x^2 + 9^2
289 = 144 + 81 + x^2
x^2 = 289 - 144 - 81
x^2 = 64
x = 8 cm
Hence, value of x cm is 8 cm.
Hope this helps you...
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