The internal length, breadth and height of a rectangular room are 6 cm, 5.2 m and 4.5 m
respectively. It has two doors each of 1.2 m by 2 m and three windows each of 1 m by 80 cm. Find
the total internal area of the room to be whitewashed. Also, find the cost of whitewashing the room
(excluding the doors and windows) at the rate of Rs. 6 per m².
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Answer:
Total area to be Whitewashing = 124.6 m^2
Total cost= Rs. 747.6
Step-by-step explanation:
Perimeter of the floor = 2*(6+5.2) m
=2* 11.2 m
= 22.4 m
Area of four walls = 22.4*4.5 m^2
= 100.8 m^2
Area of roof = 6*5.2 m^2 = 31 m^2
Tota area of two doors and three windows
= 2* 1.2*2 + 3*1*0.8 m^2
= 4.8 + 2.4 m^2
= 7.2 m^2
Total internal area of the room to be Whitewashing
=( 100.8+31-7.2 ) = 124.6 m^2
Total cost =Rs. (124.6 * 6) = Rs. 747.6
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