Question

The internal measurements of a [1] rectangular box are 3cm × 4cm × 12cm. What is the length, in centimetres, of the longest rod that will fit in the box

Answer 1

The longest rod will be the one that is placed diagonally into the box.

Find the diagonal of the base:

a² + b² = c²

3² + 4² = c²

c² = 9 + 16

c² = 25

c = √25

c = 5 cm

Find the diagonal of the box:

a² + b² = c²

5² + 12² = c²

c² = 25 + 144

c² = 169

c = √169

c = 13 cm

Answer: The longest rod is 13 cm

Answer 2

Answer-:

The longest rod will be the one that is placed diagonally in to the box.

1st

Find the diagonal of the base

p^2+b^2=h^2

3^2+4^2= h^2

=> 9+16=h^2

=> 25= h^2

=> H=√25

=> H=5cm

2nd

Find the diagonal of the box

p^2+b^2=h^2

5^2+12^2=h^2

=> 25+144=h^2

=> 169=h^2

=> H=√169

=> H=13cm

The longest rod is 13cm

Be brainly __:))