The internal measures of a cuboid hall are 13 m x 9 m x
5 m. Find the total cost of whitewashing all four walls
and ceiling of a hall, if the cost of whitewashing is 4
per m².
Answers
Answered by
9
Answer:given,
Length=13m
Breadth=9m
Height=5m
Area of four walls = area of lateral surface
=2h(l+b)
=2×5(13+9)
=10×22
=220m².
Area of ceiling =b×h
=9×5
=45m²
Cost of whitewashing per m²=4rupees
Cost of whitewashing walls and ceiling=(220+45)×4
=265×4
=1060 rupees
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Step-by-step explanation:
Answered by
4
The cuboid length = 13m
Breadth = 9m
Height=5m
Area of four walls + ceiling wall
Formula used: 2 (lh+bh)+ l×b
Putting values...
2(13×5+9×5)+13×9
=220+ 117
=337m^2
Cost of white washshing per metre = 337×4
=1348 rupees
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