The internal measures of a cuboidal box is 12×8×4 cm .Find the cost of painting all four sides of a box of the cost of painting is ₹10.5 per m² . What will be cost of painting if the top of box is also to be painted....
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Answers
2(l+b)h = LSA
2(12+8)4 =2(20)4 = 40*4 = 160m²
cost of whitewashing 4 walls =160*8 = Rs 1280
area of 5 walls = LSA+ l*b
= 160 + (12*8)
= 160 + 96
= 256m²
cost of whitewashing vd ceiling = Rs 1280 +(96*8)
= Rs 1280 + 768
= Rs 2048
Dimension of the box = 12cm * 8cm * 4cm
Area of a cuboid = 2[(l * b)+(l * h)+(b * h)]
Area of painting four sides = 2[(l * h)+(b * h)] = 2[(12*4) + (8*4)] = 2(48 + 32) = 2×80 = 160 cm² = 0.016 m²
Cost of painting four sides = 0.016 m²× ₹10.5 / m² = ₹0.168
Area including the top = 2[(l * h)+(b * h)]+(l * b) = 160 + (12*8) = 160 + 96 = 256 cm² = 0.0256 m²
Therefore cast of painting the four sides and the top of box = ₹0.0256 * 10.5 = ₹0.268