- The internal measures of a cuboidal room are 10 m x 8 mx 5 m. Find the total cost of whitewashing all four
walls of a room, if the cost of whitewashing is Rs. 5 per m. What will be the cost of white washing if
ceiling of the room is also whitewashed?
Answers
Answer:
10×8×5×m×m×m
10×40×5×5×5
400×125
48000
Please answer me as brainlist answer
Answer:
900,1300
Given,
The internal measures of a cuboidal room are 10 m * 8 m * 5 m.
To Find,
Total cost of whitewashing and Cost of whitewashing if ceiling of the room is whitewashed.
Solution,
Length of room l = 10 m.
Breadth of room b = 8 m
Height of room h = 5 m
Calculate Area of room:
- Area of room = Length * breadth
==> 10 * 8
==> 80 m^2
Area of room = 80 m^2.
Calculate Area of 4 walls:
- Area of 4 walls = 2h(l + b)
==> 2 * 5(10 + 8)
==> 10(18)
==> 180 m^2
Area of 4 walls = 180 m^2.
Area painted = 180 + 80 = 260 m^2.
Cost of whitewashing 1 m^2 = 5
Cost of whitewashing = 5 * 180 = 900.
Total cost of whitewashing = 900.
Cost of whitewashing per m^2 = 5
Cost of whitewashing 260 m^2 = 5 * 260 = 1300.
So, Rs 1300 is required to paint the 4 walls + ceiling.
Result,
Total cost of whitewashing = 900.
Cost of whitewashing if ceiling of the room is also whitewashed = 1300
#Hope my answer helped you.