the internal measures of a cuboidal room are 12 metre x 8 metre x 4 metre find the total cost of the whitewashing all four walls of the room if the cost of whitewashing is rupees 5 per metre square what will the cost of whitewashing if the selling of the room is also whitewashed
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Answered by
8
Length = 12 m
Width = 8 m
Height = 4 m
Area of four walls = 2(l+b) h
= 2(12+8) * 4
= 8*20
= 160 m^2
Area of celling = 12 * 8
= 96 m^2
Cost of white washing = (160+96) *5
= 256* 5
= Rs 1280
Width = 8 m
Height = 4 m
Area of four walls = 2(l+b) h
= 2(12+8) * 4
= 8*20
= 160 m^2
Area of celling = 12 * 8
= 96 m^2
Cost of white washing = (160+96) *5
= 256* 5
= Rs 1280
Answered by
1
LSA= 2(l+b)h
=2(12+8)4
=40×4
=160m^2
area of the walls is 160m^2
Cost= 160×5
=Rs.800
area of ceiling= 12×8
=96m^2
Cost of Ceiling=96×5
=Rs.480
Total cost=800+480
=Rs.1280
=2(12+8)4
=40×4
=160m^2
area of the walls is 160m^2
Cost= 160×5
=Rs.800
area of ceiling= 12×8
=96m^2
Cost of Ceiling=96×5
=Rs.480
Total cost=800+480
=Rs.1280
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