Question

the internal measures of a cuboidal room are 12m× 8m×4 m find the total cost of whitewashing all four walls of a room is the cost of whitewashing is rupees 5 per metre square what will be the cost of whitewashing the ceiling of the room is also whitewashed​

Answer 1

Answer: T.S.A. = 2(lb+bh+hl)

                         = 2 (96+32+48) = 2(176) = 352m^2

Cost of whitewashing = 352 x 5 = ₹1760.

PLEASE MARK BRAINLIEST BUDDY

Answer 2

Answer:

Let the length of the room=12m

Width=8m

Height=4m

Area of the four walls of the room = perimeter of the base × height of the room

=2(l+b)×h=2(12+8)×4

=160m^

Cost of whitewashing per meter=5

Hence the total cost of whitewashing for walls of the room

=160×5=800

Area of ceiling is 12× 8 = 96m^

Cost of whitewashing the ceiling=(96×5)=480

So the total cost of white washing=

(800+480)=1280