Question

The internal measures of a cuboidal room are 14m × 10m × 6m. Find the cost of painting the four walls of the room excluding two windows of size 1.5m × 0.8m each and a door of size 2m× 0.75m, if the cost of painting is ₹ 8 per m² .​

Answer 1

Answer:

this problem is solved in the above picture.

mark my answer as brainliest if it helps.

Answer 2

Given:

A  cuboidal room is 14m × 10m × 6m and two windows of size 1.5m × 0.8m each and a door of size 2m× 0.75m.

To Find:

Find the cost of painting the four walls of the room excluding two windows and a door.

Step-by-step explanation:

• We have cuboidal room with length,l= 14m breadth,b=10m and height,h=6m.

• We know curved surface area of given by 2h(l+b)

• Thus area of four walls of room is = 2h(l+b)=2(6)(14+10)=168$m^2$

• Now Given dimension of one window is  1.5m × 0.8m

                Thus area of 1 window=  1.5m × 0.8m=1.2$m^2$

                  Area of 2 windows =2  (1.2) =2.4$m^2$

• Now given dimention of door is  2m× 0.75m

          Thus area of door = 2m× 0.75m=1.5$m^2$

Thus total area need to be painted is 168-2.4-1.5=164.1$m^2$

        given cost of painting 1$m^2$=Rs 8

Hence, cost of painting 164.1$m^2$=8$\times$ 164.1= Rs 1312.8

Hence cost isRs 1312.8