the internal measures of a cuboidal room are 14m*10m*8m. find the total cost of whitewashing the 4 walls and ceiling of the room ,if the cost of whitewashing isr rupees15/m^2
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so surface area of 4 walls and ceiling=2h(l+b)+lb
=2*8(14+10)+14*10
=16*24+140
=384+140
=524m^2
so total cost=524*15
=Rs7860
=2*8(14+10)+14*10
=16*24+140
=384+140
=524m^2
so total cost=524*15
=Rs7860
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