Question

The internal measures of a cuboidal room are length 12 m, breadth 8 m and height 4 m.
Find the total cost of whitewashing all four walls and ceiling at the rate of 5 per​

Answer 1

Answer:

₹ 1280

Step-by-step explanation:

Area to be whitewashed = LSA + Ceiling

$= 2h(l + b) + lb \\ = 2 \times 4(12 + 8) + (12 \times 8) \\ = (8 \times 20) + 96 \\ = 160 + 96 = 256 {m}^{2}$

Cost = Area to be washed × Rate

= 256 × 5 = ₹ 1280

Thus, the cost of whitewashing will be ₹ 1280.