The internal resistance of a cell of emf 2V is 0.1Ω It is connected to a resistance of 3.9Ω. The voltage across the cell will be:
a) 0.5V
b) 1.5V
c) 1.95V
d) 2V
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It is connected to a resistance of 3.9 ohm. The voltage across the cell is 0.5V.
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C
1.95 V
r is the internal resistance.
R is the external resistance.
ε is the emf of the cell.
Using Kirchoff's voltage law, −2+I(r+R)=0
I= 42 =0.5A
Potential difference across the cell,V=ε−Ir=2−0.05=1.95V
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