Question

The internal resistance of a cell of emf 2V is 0.1 ohm, it is connected to a resistance of 0.9 ohm. The voltage across the cell will be... *

1) 0.5 V

2) 1.8 V

3) 1.95 V

4) 3V


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Answer 1

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A resistor of resistance 3.9Ω is connected in series with internal resistance of cell 0.1Ω.

Total resistance of the circuit R′=0.1+3.9=4.0Ω

Emf of cell E=2V

Current flowing in the circuit I=R′E

∴ I=42=0.5A

Thus voltage across the cell Vcell=IR where R=3.9Ω

⟹ Vcell=0.5×3.9=1.95V 

Answer 2

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•A resistor of resistance 3.9Ω is connected in series with internal resistance of cell 0.1Ω.

•Total resistance of the circuit R′=0.1+3.9=4.0Ω

Emf of cell E=2V

•Current flowing in the circuit I=R′E

∴ I=42=0.5A

•Thus voltage across the cell Vcell=IR where R=3.9Ω

⟹ Vcell=0.5×3.9=1.95V 

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