Question

The internal resistance of a cell of emf 2V is 0.1 ohm. It is connected to a resistance of 3.9 ohm. The voltage across the cell is










0.5V







1.9V







2V







1.95V
AND EXPLAIN

Answer 1

E =2V
r=0.1 ohm
R=3.9 ohm

E=I(r+R)
2=I(0.1+3.9)
2=I×4
I=2/4=0.5A


voltage across cell

V=IR
=0.5×3.9
=1.95V


Hence d is the answer dude.

Answer 2

Answer:

The voltage across the cell is 1.95 V.

(d) is correct option.

Explanation:

Given that,

Emf = 2 V

Internal resistance = 0.1 ohm

Resistance = 3.9 ohm

We need to calculate the current

Using formula of emf

$E=IR$

$I=\dfrac{E}{R}$

Put the value into the formula

$I=\dfrac{2}{3.9}$

$I=0.5\ A$

We need to calculate the voltage

Using formula of voltage

$V = E-Ir$

$V= 2-0.5\times0.1$

$V=1.95\ V$

Hence, The voltage across the cell is 1.95 V.