Question

The internal resistance of cells is 0.192 and
its emf is 2V. When a current of 2A is
being drawn from it, the potential
difference across its terminals will be :
(a) more than 2V(b) 2V
(C) 1.8V
(d) OV​

Answer 1

Answer:

V=E-ir here E is 2 v, I is 2 A , r is 0.192 ohm .... V= 2-(2×0.192)..... V=2-0.384, V=1.616v