Question

the internal resistances of two cells are 0.1 ohm and 0.3 ohm and emf of 2 volt each are connected in series.if R is equal to 0.2 ohm the potential difference across the cell is

Answer 1

Answer:

answer is zero ...

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Answer 2

Answer:

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Explanation:

Applying Kirchhoffs voltage law across the circuit assuming current I we have :

−(0.2)I−(0.3)I+2V−(0.1)+3V=0

⇒0.61=4

⇒I=  40/6  =  20 /3 Ω

For Potential difference across B, moving across it we have :

V  1  −(0.3)  20/3  +2V=V  2

​⇒V  1 −2V+2V=V  2

​⇒V  1  =V  2

​So potential difference across B is 0