Question

The intersection of two streets forms a parallelogram. One street is 40 feet wide. The height of the parallelogram formed is 25 ft. What is the area of the intersection?

A. 500 sq ft
B. 560 sq ft
C. 1,000 sq ft
D. 1,120 sq ft

Answer 1

Answer:

as we know the area of Parallelogram is bh u². i.e base ×height u²

Here the base is 40ft and the height is 25ft.

Therefore the area will be(40×25)ft²=1000ft²

It is ur answer buddy with explanation.

Option C

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Answer 2

$\underline{\bold{\huge{\color{purple}{\longrightarrow{ANSWER}{\longleftarrow}}}}}$

☞ Given :

Measurement of one street ( base ) = 40 feet wide .

Height of the parallelogram = 25 feet wide .

✐ Required to find :

1. Area of the intersection .

❁ Formula used :

$\longrightarrow{\boxed{\Rightarrow{\boxed{\color{maroon}{Area of the parallelogram = base \times height}}}}}$

✯ Explanation :

➞ In the question it is given that

➞ The intersection of the two streets forms a parallelogram

➞ One street of 40 feet wide will become as the base of the parallelogram .

➞ Similarly ,

➞ It is also given that the height of the parallelogram is 25 feet wide .

➞ Hence, from the above statements it is concluded that ;

✪ Base of the parallelogram is 40 feet wide .

✪ Height of the parallelogram is 25 feet wide .

↛Therefore,

↛ Using the mentioned formula we can find the area of the intersection .

✧ Solution :

↛The given values ;

• Base of the parallelogram = 40 feet wide
• Height of the parallelogram = 25 feet wide

✪ Mentioned formula

$\longrightarrow{\fbox{\color{blue}{\Rightarrow{\fbox{\color{green}{Area of the parallelogram = base \times height}}}}}}$

Hence,

$\longrightarrow{Area of the parallelogram = 40 feet \times 25 feet }$

$\implies{Area of the parallelogram = 1000 {feet}^{2} }$

Therefore,

$\longrightarrow{\boxed{\Rightarrow{\fbox{\color{red}{Area of the intersection = 1000 {feet}^{2} }}}}}$

$\underline{\bigstar{\bold{\huge{\blue{Option}{\green{-}{\red{C}}}}}}}$

✅ Hence Solved ⇖