Math, asked by BrainlyHelper, 1 year ago

The interval in which is increasing is (A) (B) (−2, 0) (C) (D) (0, 2)

Answers

Answered by abhi178
0
The interval in which \bf{y=x^2e^{-x}} is increasing is
A. (– ∞, ∞)
B. (– 2, 0)
C. (2, ∞)
D. (0, 2)

solution :- we know function f(x) is increasing on interval [a,b] only when f'(x) > 0 in interval [a,b].

y=x^2e^{-x}\\\\\text{differentiate with respect to x}\\y'=2xe^{-x}+x^2(-e^{-x})\\y'=xe^{-x}(2-x)>0

here e^{-x} is an exponential function.
so, it is always positive .
e.g., x (positive)(2 - x ) > 0
=> x(2 - x) > 0
=> 0 < x < 2

hence, f(x) = x^2e^{-x} is increasing on (0,2).

hence, option (d) is correct.
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