The interval in which the function f(x) = 2x3 – 3x2 – 36x + 7 is strictly decreasing is
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Strictly decreasing means the slope of curve should be negative
So first differentiating wrt to x we get
f'(x)=6x^2-6x-36
6x^2-6x-36<0
x^2-x-6<0
x^2-3x+2x-6<0
x(x-3)+2(x-3)<0
(x-3)(x+2)<0
hope you know wavy curve method further
If u get stuck tell me I would upload that too
hope it helps
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So first differentiating wrt to x we get
f'(x)=6x^2-6x-36
6x^2-6x-36<0
x^2-x-6<0
x^2-3x+2x-6<0
x(x-3)+2(x-3)<0
(x-3)(x+2)<0
hope you know wavy curve method further
If u get stuck tell me I would upload that too
hope it helps
Tap the blue crown
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