Question

The Inverse h- when h(x) log10x is ​

Answer 1

Answer:

Step-by-step explanation:

We have,

$\displaystyle\sf{h(x)=\log_{10}(x)}$

$\tt{Let\,\,\,y=h^{-1}(x)}$

$\sf{\implies\,h(y)=x}$

$\displaystyle\sf{\implies\,\log_{10}(y)=x}$

$\displaystyle\sf{\implies\,y=10^x}$

$\displaystyle\sf{\implies\,h^{-1}(x)=10^x}$