Question

The inversion temperature for van der Waal's gas is :
(a) Tᵢ = a/(Rb) (b) Tᵢ = (2a/Rb)
(c) Tᵢ = 0.5 T (d) Tᵢ = a/2(R / b)

Answer 1

The equation of inversion temperature for van der Waal's gas is  Tᵢ = (2a/Rb).

Option (B) is correct.

Explanation:

• The temperature above which a gas hots up upon expansion is called inversion temperature.
• Its value is  Tᵢ = (2a/Rb)
• Where Ti = Inversion temperature
• In thermodynamics and cryogenics this is the point at which a non-ideal gas  that is expanding at constant enthalpy will experience a fall in the temperature.

Thus the equation of inversion temperature for van der Waal's gas is  Tᵢ = (2a/Rb).

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Answer 2

The inversion temperature for van der Waal's gas is $\bold{T_{i}=\frac{2a}{Rb}}$

Step by step explanation:

Gases become cooler during Joule Thomson's expansion only if they are below a certain temperature known as inversion temperature $\bold{T_{i}}$.

The inversion temperature can be calculated by the following formula.

                                   $\bold{T_{i} = \frac{2a}{bR}}$......................(1)

From the given,

a =  constant

b = constant

R = $0.0821\,L\,atm\,K^{-1}\,mol^{-1}$                                      

                                     

Therefore, The inversion temperature for van der Waal's gas is $\bold{T_{i}=\frac{2a}{Rb}}$

Hence, correct option is "b".

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