Question

The ionic conductance of Ba2+ and Cl- are 127 and 76 per ohm cm2.Find the equivalent conductance of BaCl2

Answer 1

Answer: The equivalent conductance of$BaCl_2 \text{ is }279ohm^{-1}cm^2mol^{-1}$

Explanation: To calculate the equivalent conducatnce at infinite dilution, we use the formula:

$\Lambda_{eq}^{\infty}=\lambda_c^o+\lambda_a^o$

For $BaCl_2$, the  equivalent conductance will be:

$\Lambda_{eq}^{\infty}=\lambda_{Ba^{2+}}^o+2\lambda_{Cl^-}^o$

We are given:

$\lambda_{Ba^{2+}}^o=127ohm^{-1}cm^2mol^{-1}$

$\lambda_{Cl^-}^o=76ohm^{-1}cm^2mol^{-1}$

Putting values in above equation, we get:

$\Lambda_{eq}^{\infty}=[127+2(76)]ohm^{-1}cm^2mol^{-1}=279ohm^{-1}cm^2mol^{-1}$

The equivalent conductance of$BaCl_2 \text{ is }279ohm^{-1}cm^2mol^{-1}$

Answer 2

Explanation:

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