Question

The ionic product of water at 25 c 10^14. Its ionic product at 90℃ will be

Answer 1

H₂O ⇄ H⁺ + OH⁻

Water dissociates in this manner. Now ionic product of water is Kw

Kw = [H⁺][OH⁻] mol²dm⁻⁶

Kw is a constant for water in a particular temperature.

With increase in temperature Kw increases and if the temperature is decreased the Kw value decreases.

In higher temperature the equilibrium of the stated equation shifts to the right, so more dissociation occurs leading increase in Kw value, with decrease temperature the equilibrium shifts left and Kw value decreases.

At 90°C the Kw value of water is 38 X 10⁻¹⁴ mol²dm⁻⁶.

Answer 2

Answer:

Explanation:  At 25 c ionic product is 10^-14 .With increase in temperature to 90 c its kw value also increases so the ionic product [ H⁺][OH ] will be greater than 10^-14