Question

The ionic product of water at 50°C is 4 x 10-14. The pH of water is:
(a) 6.3 and it is acidic
(b) 7 and it is neutral
(c) 6.7 and it is neutral
(d) 7.3 and it is basic
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Answer 1

Explanation:

c it is neutral 6.7 it's pHvalue

Answer 2

Answer:

The ionic product of water at 50°C is 4 x 10-14.

Explanation:

The correct option is B 6.8

Ionic product of water =2.7×10−14

H2O→H++OH−

x x

[H+][OH−]=2.7×10−14

x2=2.7×10−14

x=√2.7×10−14=1.7×10−7

pH−log[H+]

=−log[1.7×10−7]=[0.2304−7]

=+6.7696

pH=6.8

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