Question

The ionic product of water is 10-14(mol/l)2.The number of H+ions that present in one millionth part of 1 ml of pure water is

Answer 1

ionic product mean products of concentration of[ H+]and [OH-] ions
we also know
in pure water concentration of H+ =10^-7mole/l

number of mole of water in Given situation=10^-7x (1ml/1000000)=10^-7x10^-9=10^-16mole

now use avogadro law
1 mole contains 6.023x10^23 no of atom/ions
so, 10^-16 mole contains 6.023x10^(23-16)=6.023x10^7 ions

Answer 2

ionic product mean products of concentration of[ H+]and [OH-] ions

we also know

in pure water concentration of H+ =10^-7mole/l

number of mole of water in Given situation=10^-7x (1ml/1000000)=10^-7x10^-9=10^-16mole

now use avogadro law

1 mole contains 6.023x10^23 no of atom/ions

so, 10^-16 mole contains 6.023x10^(23-16)=6.023x10^7 ions