Question

The ionic radii of Cs and CI are 0.165 nm and I am respectively and their atomic weights are 133
and 35.5. Calculate the density of CSCL​

Answer 1

4.31×103kgm3

Explanation:

The lattice parameter of CsCI is, 2(r++r−)=a√3 , now the ionic radii of Cs and CI are 0.165 nm and 0.181 nm respectively. So, the lattice parameter (a) is 0.4 nm, option A is correct. So, the density of CsCI is 4.31×103kgm3 option C is correct.