Chemistry, asked by Bsahiner5467, 1 year ago

The ionic radii of rb+ and i- are 1.46 and 2.16 respectively, the most probable type of structure exhibited by it is

Answers

Answered by IlaMends
39

Answer:The Crystal structure is octahedral.

Explanation:

Ionic radii of the cation =r_+=1.46

Ionic radii of the anion =r_-=2.16

Radius ratio = \frac{\text{Radius of the cation}}{\text{Radius of the anion}}

The radius ratio of the ionic crystal lattice = \frac{r_+}{r_-}=\frac{1.46}{2.16}=0.675

The radius ratio given for the crystal lattice is 0.675 which lies in between the range of 0.414 to 0.732 for 6 coordination number. The Crystal structure with 6 coordination number octahedral.

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