Question

The ionisation energy of 10times ionised sodium atom is

1-3.6eV

2-136x11 eV

3-13.6/(11)^2 eV

4-13.6x(11)^2

Answer 1

D is the correct option......
hope it helps u......

Answer 2

Answer:

The ionization energy of 10 times ionized sodium atom is $13.6\times(11)^2$.

Explanation:

Ionization energy : The minimum amount of energy which must be supplied to an isolated gaseous atom to lose the valence electron .It is represents by $E_{i}$.

When the electron will be at infinity then the ionization energy of electron as assume to be zero. Because the electron is very far distance from the nucleus.

We know that,

$E_{i}=E_{\infty}-E_{i}$

$E_{i}=0-(\dfrac{-E_{0}\times z^2}{n^2})$

$E_{i}=0-(\dfrac{-13.6\times(11)^2}{1^2})$

$E_{i}=13.6\times(11)^2$

Hence, The ionization energy of 10 times ionized sodium atom is $13.6\times(11)^2$.