Question

The ionisation energy of H-atom (in the ground
state) is x kJ. The energy required for an electron
to jump from 2nd to 3rd orbit will be​

Answer 1

Answer:

Ionization energy of H means

$x( \frac{1}{1 {}^{2} } - \frac{1}{ \infty {}^{2} } )$

So required energy

$x( \frac{1}{ {2}^{2} } - \frac{1}{ {3}^{2}} ) = x( \frac{9 - 4}{36} ) = \frac{5x}{36}$

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