The ionisation energy of H-atom (in the ground
state) is x kJ. The energy required for an electron
to jump from 2nd to 3rd orbit will be
(1) x/6
(2) 5x
(3) 7.2x
(4) 5x/36
Answers
Answered by
1
Explanation:
The energy of an electron in the n
th
orbit of hydrogen atom =
n
2
−13.6
eV.
I.E.=+13.6 eV=x kJ
The energy difference of 2
nd
and 3
rd
orbit
ΔE=x[
4
1
−
9
1
] kJ
ΔE=x×
36
5
kJ
ΔE=
36
5x
kJ
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