Chemistry, asked by raziahassan1104, 6 months ago

The ionisation energy of H-atom (in the ground
state) is x kJ. The energy required for an electron
to jump from 2nd to 3rd orbit will be
(1) x/6
(2) 5x
(3) 7.2x
(4) 5x/36​

Answers

Answered by Anonymous
1

Explanation:

The energy of an electron in the n

th

orbit of hydrogen atom =

n

2

−13.6

eV.

I.E.=+13.6 eV=x kJ

The energy difference of 2

nd

and 3

rd

orbit

ΔE=x[

4

1

9

1

] kJ

ΔE=x×

36

5

kJ

ΔE=

36

5x

kJ

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